![[personal profile]](https://www.dreamwidth.org/img/silk/identity/user.png){kind=small}
well, time for some math.
Apr. 1st, 2013 01:33 pmSO: I did a 4X4 inch swatch, and ran it through the hot cycle of the washer a couple of times...and ended up with a 3.5" (wide) by 3" (tall) swatch.
OK: so the catbed is (at the rim) 190 st. at 12 st/4 in, that should be (190/12)*4 = 63" in circumference, which seems about right (it's on 60" circulars, with some bunching). If it shrinks to 3.5 in/12 st, that would be (190/12)*3.5 = 55" in circumference.
circumference=diameter*pi, so diameter=circumference/pi. So the diameter of the current huge mass should be ~20", and that of the felted one would be ~17.5". Which would be about right.
Except the current huge mass seems like it's gotta be more than 20" across. Guess I should lay it out this evening and see if I can get an idea (aka, convince myself it will work out).
Because I really don't want to frog the whole blasted thing.
OK: so the catbed is (at the rim) 190 st. at 12 st/4 in, that should be (190/12)*4 = 63" in circumference, which seems about right (it's on 60" circulars, with some bunching). If it shrinks to 3.5 in/12 st, that would be (190/12)*3.5 = 55" in circumference.
circumference=diameter*pi, so diameter=circumference/pi. So the diameter of the current huge mass should be ~20", and that of the felted one would be ~17.5". Which would be about right.
Except the current huge mass seems like it's gotta be more than 20" across. Guess I should lay it out this evening and see if I can get an idea (aka, convince myself it will work out).
Because I really don't want to frog the whole blasted thing.
